What is the quantity of sugar charcoal remaining behind after charring 17.1 g sugar using conc.…
What is the quantity of sugar charcoal remaining behind after charring 17.1 g sugar using conc. $\mathrm{H}_2 \mathrm{SO}_4$ under ideal conditions?
- 7.2 g
- 14.4 g
- 10.5 g
- 11.4 g
Solution
$\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11} \underset{-11 \mathrm{H}_2 \mathrm{O}}{\longrightarrow} 12 \mathrm{C}$
$\frac{17.1}{342}=0.05 \text { moles } 0.6 \mathrm{~mol}$
Mass of charcoal $=0.06 \times 12=7.2 \mathrm{~g}$
Asked in: MHT CET 2022 (11 Aug Shift 1)
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