What is the percentage hydrolysis of $\mathrm{NaCN}$ in $\mathrm{N} / 80$ solution when the dissociation…

What is the percentage hydrolysis of $\mathrm{NaCN}$ in $\mathrm{N} / 80$ solution when the dissociation constant for $\mathrm{HCN}$ is $1.3 \times 10^{-9}$ and $\mathrm{K}_{\mathrm{w}}=1.0 \times 10^{-14}$
  1. $2.48$
  2. $5.26$
  3. $8.2$
  4. $9.6$

Solution

$\alpha=\sqrt{\frac{\mathrm{K}_{\mathrm{w}}}{\mathrm{K}_{\mathrm{a}} \times \mathrm{c}}}=\sqrt{\frac{10^{-14}}{1.3 \times 10^{-9} \times \frac{1}{80}}}=2.48 \%$. *

Asked in: JEE-TOPICTESTS-CHEMISTRY

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