What is the percentage dissociation of $0.1 \mathrm{M}$ acetic acid? $\left(\mathrm{Ka}=10^{-5}\right)$
What is the percentage dissociation of $0.1 \mathrm{M}$ acetic acid?
$\left(\mathrm{Ka}=10^{-5}\right)$
- $1 \%$
- $10 \%$
- $0.1 \%$
- $0.01 \%$
Solution
$\begin{aligned} & \mathrm{K}_{\mathrm{a}}=\propto^2 \mathrm{C} \\ & 10^{-5}=\propto^2 \times 0.1 \\ & \propto=0.01 \text { or } 1 \%\end{aligned}$
Asked in: MHT CET 2022 (11 Aug Shift 1)
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