What is the oxidation state of S in $\mathrm{SO}_4^{2-}$ ?

What is the oxidation state of S in $\mathrm{SO}_4^{2-}$ ?
  1. +6
  2. -6
  3. +2
  4. +3

Solution

Let the oxidation state of S in $\mathrm{SO}_4^{2-}=x$ $\begin{array}{ll} & x+4(-2)=-2 \\ \therefore \quad & x-8=-2 \\ \therefore \quad & x=8-2=+6 \end{array}$

Asked in: MHT CET 2024 (04 May Shift 2)

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