What is the oxidation state of carbon in $\mathrm{CaC}_2$ and $\mathrm{K}_2 \mathrm{C}_2 \mathrm{O}_4$…

What is the oxidation state of carbon in $\mathrm{CaC}_2$ and $\mathrm{K}_2 \mathrm{C}_2 \mathrm{O}_4$ respectively?
  1. -2 and +6
  2. -1 and +3
  3. +2 and +2
  4. -2 and +3

Solution

$\begin{array}{ll} & \mathrm{CaC}_2 \\ & +2+(x \times 2)=0 \text { or } x=-1 \\ & \mathrm{~K}_2 \mathrm{C}_2 \mathrm{O}_4 \\ \therefore \quad & (+1 \times 2)+(x \times 2)+(-2 \times 4)=0 \text { or } x=+3\end{array}$

Asked in: MHT CET 2023 (09 May Shift 1)

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