What is the oxidation number of $\mathrm{Br}$ in $\mathrm{KBrO}_4$ ?

What is the oxidation number of $\mathrm{Br}$ in $\mathrm{KBrO}_4$ ?
  1. $+6$
  2. $+7$
  3. $+5$
  4. $+8$

Solution

Let the oxidation no. of $\mathrm{Br}$ be $x$. $\begin{aligned} \text { In } \mathrm{KBrO}_4+1+x+4(-2) & =0,-7+x=0 \\ x & =+7\end{aligned}$

Asked in: NEET 2022 (Phase 2)

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