What is the oxidation number of Carbon in $\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$?
What is the oxidation number of Carbon in $\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4}$?
- $+3$
- $-2$
- 0
- $+4$
Solution
$\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \Rightarrow(1 \times 2)+(\mathrm{x} \times 2)+(-2 \times 4)$
$=2+2 x-8$
$=2 x-6$
$\therefore x=+3$
$\therefore$ The oxidation number of $C=+3$
Asked in: MHT CET 2020 (20 Oct Shift 2)
Practice more Redox Reactions questions on Aicharya