What is the osmotic pressure of solution prepared by dissolving 3 gram solute in $2 \mathrm{dm}^3$ water at…

What is the osmotic pressure of solution prepared by dissolving 3 gram solute in $2 \mathrm{dm}^3$ water at 300 K . (Molar mass of solute $=60 \mathrm{~g} \mathrm{~mol}{ }^{-1}$, $\mathrm{R}=0.0821 \mathrm{dm}^3 \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}$ )
  1. 0.76 atc m
  2. 0.62 atm
  3. 0.51 atm
  4. 0.84 atm

Solution

$\begin{aligned} & \pi=\mathrm{MRT} \\ & \pi=\frac{\mathrm{n}_2 \mathrm{RT}}{\mathrm{V}}=\frac{\frac{3}{60} \times 0.082 \times 300}{2}=0.62 \mathrm{~atm}\end{aligned}$

Asked in: MHT CET 2024 (09 May Shift 1)

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