What is the osmotic pressure (in atm) of $0.02 \mathrm{M}$ aqueous glucose solution at $300 \mathrm{~K}$ ?…

What is the osmotic pressure (in atm) of $0.02 \mathrm{M}$ aqueous glucose solution at $300 \mathrm{~K}$ ? $\left(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}{ }^{-1} \mathrm{~K}^{-1}\right)$
  1. $\frac{1}{0.492}$
  2. 0.492
  3. 0.988
  4. $\frac{1}{0.988}$

Solution

$\begin{aligned} & \pi=\mathrm{CRT}=(0.02)(0.082)(300) \\ & =0.492 \mathrm{~atm} .\end{aligned}$

Asked in: AP EAMCET 2023 (16 May Shift 1)

Practice more Solutions questions on Aicharya