What is the order of following reaction $2 \mathrm{H}_2 \mathrm{O}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}_{(1)}+\mathrm{O}_{2(\mathrm{~g})}$

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Aicharya · Accepted Answer

General Rate Law for Decomposition of Hydrogen Peroxide: The decomposition of hydrogen peroxide is often described by the rate law: $\text {Rate }=k\left[\mathrm{H}_2 \mathrm{O}_2\right]^n$
Where: - $k$ is the rate constant, - $n$ is the order of the reaction with respect to $\mathrm{H}_2 \mathrm{O}_2$.
Common Information: The decomposition of hydrogen peroxide is typically a second-order reaction with respect to $\mathrm{H}_2 \mathrm{O}_2$, meaning the rate is proportional to the square of the concentration of hydrogen peroxide.

What is the order of following reaction $2 \mathrm{H}_2 \mathrm{O}_{2(\mathrm{~g})} \longrightarrow 2…

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