What is the $\mathrm{pH}$ of the solution containing $1.342 imes 10^{-3} \mathrm{M} \mathrm{H}^{+}$ ions? $(\log 1.342=0.1277)$

Question

What is the $\mathrm{pH}$ of the solution containing $1.342 	imes 10^{-3} \mathrm{M} \mathrm{H}^{+}$ ions? $(\log 1.342=0.1277)$

Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{pH}=-\log \left[\mathrm{H}^{+}ight] \ & =-\log \left(1.342 	imes 10^{-3}ight) \ & =3-\log 1.342 \ & =3-0.1277 \ & =2.87\end{aligned}$

What is the $\mathrm{pH}$ of the solution containing $1.342 \times 10^{-3} \mathrm{M} \mathrm{H}^{+}$ ions?…

Solution