What is the $\mathrm{pH}$ of solution containing $4.62 imes 10^{-4} \mathrm{M} \mathrm{H}^{+}$ions?

Question

What is the $\mathrm{pH}$ of solution containing $4.62 	imes 10^{-4} \mathrm{M} \mathrm{H}^{+}$ions?

Aicharya · Accepted Answer

$\begin{aligned} \mathrm{pH} & =-\log _{10}\left[\mathrm{H}^{+}ight] \ & =-\log _{10}\left(4.62 	imes 10^{-4}ight) \ & =-\left[\log _{10} 4.62+\left(\log _{10} 10^{-4}ight)ight] \ & =-[0.6646-4] \ & =3.3354\end{aligned}$

What is the $\mathrm{pH}$ of solution containing $4.62 \times 10^{-4} \mathrm{M} \mathrm{H}^{+}$ions?

Solution