What is the number of unpaired electrons present in $\mathrm{f}$-orbital at +3 oxidation state of…

What is the number of unpaired electrons present in $\mathrm{f}$-orbital at +3 oxidation state of $\mathrm{Lu}(\mathrm{Z}=71)$ ?
  1. 0
  2. 4
  3. 2
  4. 7

Solution

$\mathrm{Lu}=[\mathrm{Xe}] 4 \mathrm{f}^{14} 5 \mathrm{~d}^1 6 \mathrm{~s}^2$ or $\mathrm{Lu}^{+3}=[\mathrm{Xe}] 4 \mathrm{f}^{14}$

Asked in: MHT CET 2022 (05 Aug Shift 2)

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