What is the number of octahedral voids present in 0.2 mol of a compound forming hep structure?
What is the number of octahedral voids present in 0.2 mol of a compound forming hep structure?
$1.204 \times 10^{23}$
$2.387 \times 10^{23}$
$3.011 \times 10^{23}$
$3.321 \times 10^{23}$
Solution
Number of atoms in 0.2 mol of the compound $=0.2 \times \mathrm{N}_{\mathrm{A}}=0.2 \times 6.022 \times 10^{23}$ $=1.2044 \times 10^{23}$ atoms
a. Number of octahedral voids
$\begin{aligned}
& =\text { Number of atoms } \\
& =1.2044 \times 10^{23}
\end{aligned}$