What is the number of electrons present in antibonding orbitals of $\mathrm{N}_2$ molecule according to molecular orbital theory?

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Aicharya · Accepted Answer

The electronic configuration of $\mathrm{N}_2$ molecule is $(\sigma 1 \mathrm{~s})^2\left(\sigma^* 1 \mathrm{~s}\right)^2(\sigma 2 \mathrm{~s})^2\left(\sigma^* 2 \mathrm{~s}\right)^2\left(\pi 2 \mathrm{p}_{\mathrm{x}}\right)^2\left(\pi 2 \mathrm{p}_{\mathrm{y}}\right)^2\left(\sigma 2 \mathrm{p}_{\mathrm{z}}\right)^2$ $\therefore \quad$ No. of electrons in antibonding orbitals $=4$

What is the number of electrons present in antibonding orbitals of \(\mathrm{N}_2\) molecule according to…

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