What is the number of electrons lost by Cr in a complex $\left[\mathrm{Cr}(\mathrm{CO})_6\right]$ ?

What is the number of electrons lost by Cr in a complex $\left[\mathrm{Cr}(\mathrm{CO})_6\right]$ ?
  1. 0
  2. 4
  3. 6
  4. 2

Solution

Since carbonyl (CO) is a neutral ligand, oxidation state of Cr in $\left[\mathrm{Cr}(\mathrm{CO})_6\right]$ is 0 . Hence, no electron will be lost by Cr . in the complex.

Asked in: MHT CET 2024 (15 May Shift 1)

Practice more Coordination Compounds questions on Aicharya