What is the molarity of $\mathrm{SO}_{4}^{2-}$ ion in aqueous solution that contain $34.2 \mathrm{ppm}$ of…
(Assume complete dissociation and density of solution $1 \mathrm{~g} / \mathrm{mL}$)
- $3 \times 10^{-4} \mathrm{M}$
- $2 \times 10^{-4} \mathrm{M}$
- $10^{-4} \mathrm{M}$
- None of these
Solution
mass of water
litre solution contains $1000 \mathrm{~g}$ of water $\Rightarrow$ In 1 litre solution, mass of
$\mathrm{Al}_{2}\left(\mathrm{SO}_{4}ight)_{3}=\frac{34.2 \times 1000}{10^{6}}=34.2 \mathrm{mg}$
molarity of
$\mathrm{Al}_{2}\left(\mathrm{SO}_{4}ight)_{3}=\frac{34.2 \times 10^{-3}}{342} \mathrm{M}=10^{-4} \mathrm{M}$
$\mathrm{Al}_{2}\left(\mathrm{SO}_{4}ight)_{3}(\mathrm{aq}) \longrightarrow 2 \mathrm{Al}^{3+}(\mathrm{aq})+3 \mathrm{SO}_{4}^{2-}(\mathrm{aq})$
$10^{-4} \mathrm{M}$ $\quad$$\quad$$\quad$$\quad$$2 \times 10^{-4} \mathrm{M} \quad 3 \times 10^{-4} \mathrm{M}$
$\left[\mathrm{SO}_{4}^{2-}ight]=3 \times 10^{-4} \mathrm{M}$ ,
Asked in: JEE-TOPICTESTS-CHEMISTRY
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