What is the molar conductivity at infinite dilution of $\mathrm{CaCl}_{2}$, if the molar conductivity of…

What is the molar conductivity at infinite dilution of $\mathrm{CaCl}_{2}$, if the molar conductivity of $\mathrm{Ca}^{2+}$ ion and $\mathrm{Cl}^{-}$ ion at infinite dilution is 119 and $71 \Omega^{-1} \mathrm{~cm}^{2}$ $\mathrm{mol}^{-1}$
  1. $431 \cdot 0 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
  2. $341 \cdot 0 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
  3. $261 \cdot 0 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
  4. $126 \cdot 0 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$

Solution

By Kohlrausch Law of independent migration of ions, $\begin{aligned} \wedge_{0\left(\mathrm{CaCl}_{2}\right)} &=\lambda_{\mathrm{Ca}^{2+}}^{0}+2 \lambda_{\mathrm{Cl}^{-}}^{0} \\ &=119+2(71) \\ &=261.0 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \end{aligned}$

Asked in: MHT CET 2020 (14 Oct Shift 1)

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