What is the minimum quantity (in grams) of methyl iodide required for preparing one mole of ethane by Wurtz…
What is the minimum quantity (in grams) of methyl iodide required for preparing one mole of ethane by Wurtz reaction?
(Atomic weight of iodine $=127$ )
$142$
$568$
$326$
$284$
Solution
Wurtz reaction for the preparation of ethane is
$
\underset{1}{\mathrm{CH}_3 \mathrm{I}+2 \mathrm{Na}}+\underset{\mathrm{ICH}}{\mathrm{ICH}_3} \stackrel{\text { dry ether }}{\longrightarrow} \underset{1 \mathrm{~mole}}{\mathrm{C}_2 \mathrm{H}_6}+2 \mathrm{NaI}
$
$1 \mathrm{~mole} \quad 1 \mathrm{~mole} \quad 1 \mathrm{~mole}$
Number of moles of $\mathrm{CH}_3 \mathrm{I}$ required for the manufacture of 1 mole $_2 \mathrm{H}_6=2$ moles
Weight of 2 moles of $\mathrm{CH}_3 \mathrm{I}$
$
\begin{aligned}
& =2 \times(12+3+127) \\
& =2 \times(142) \\
& =284 \mathrm{~g}
\end{aligned}
$