What is the minimum concentration of $\mathrm{SO}_{4}^{2}$ required to precipitate $\mathrm{BaSO}_{4}$ in a…
- $4 \times 10^{-10} \mathrm{M}$
- $2 \times 10^{-7} \mathrm{M}$
- $4 \times 10^{-6} \mathrm{M}$
- $2 \times 10^{-3} \mathrm{M}$
Solution
$\mathrm{K}_{\mathrm{sp}}=\left(1.0 \times 10^{-4}ight)\left[\mathrm{SO}_{4}^{2-}ight]=4 \times 10^{-10}$
$\therefore\left[\mathrm{SO}_{4}^{2-}ight]=4 \times 10^{-6} \mathrm{M}$ ~
Asked in: JEE-TOPICTESTS-CHEMISTRY