What is the mass of $33.6 \mathrm{dm}^3$ of methane gas at S.T.P.?
What is the mass of $33.6 \mathrm{dm}^3$ of methane gas at S.T.P.?
- $4.8 \times 10^{-2} \mathrm{~kg}$
- $3.3 \times 10^{-2} \mathrm{~kg}$
- $1.6 \times 10^{-2} \mathrm{~kg}$
- $2.4 \times 10^{-2} \mathrm{~kg}$
Solution
$\begin{aligned} & \text { moles of gas }=\frac{\text { volume }}{22.4}=\frac{33.6}{22.4}=1.5 \\ & \text { mass of } \begin{aligned}\left(\mathrm{CH}_4\right) \text { methane gas } & =\text { moles } \times \text { molar mass } \\ & =1.5 \times 16 \\ & =24 \mathrm{~g} \\ & =2.4 \times 10^{-2} \mathrm{~kg}\end{aligned}\end{aligned}$
Asked in: MHT CET 2021 (23 Sep Shift 2)
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