What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series?

( $h =$ Planck's constant, $c =$ velocity of light, $R =$ Rydberg's constant).

Question

What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series? ( h = Planck's constant, c = velocity of light, R = Rydberg's constant).

Aicharya · Accepted Answer

We know that, ∆ E = h c · R 1 n 1 2 - 1 n 2 2 For lowest energy, of the spectral line in Lyman series, n 1 = 1 , n 2 = 2 Hence, ∆ E = h c . R 1 1 2 - 1 2 2 ∆ E = 3 h c R 4 *

What is the lowest energy of the spectral line emitted by the hydrogen atom in the Lyman series? ( h =…

Solution