What is the lateral shift of a ray refracted through a parallel-sided glass slab of thickness ' $h$ ' in…
- $\frac{h \tan (i-r)}{\tan r}$
- $\frac{h \sin (i-r)}{\cos r}$
- h
- $\frac{h \cos (i-r)}{\sin r}$
Solution

$\begin{aligned} & A B=h \sec r \\ & B C=h \sec r \sin (\bar{i}-r) \\ & B C=\frac{h \sin (i-r)}{\cos r}\end{aligned}$
Asked in: JEE Main 2025 (23 Jan Shift 1)