What is the half life of a first order reaction if time required to decrease concentration of reactant from…
What is the half life of a first order reaction if time required to decrease concentration of reactant from 0.8 M to 0.2 M is 12 hour?
- 1.5 hour
- 3 hour
- 6 hour
- 12 hour
Solution
For the first order reaction,
$\begin{array}{ll}
& k=\frac{2.303}{t} \log _{10} \frac{[\mathrm{~A}]_0}{[\mathrm{~A}]_{\mathrm{t}}}=\frac{2.303}{12 \text { hour }} \log _{10} \frac{[0.8]}{[0.2]} \\
\therefore & \mathrm{k}=0.1919 \times 0.6020=0.1155 \text { hour }^{-1} \\
\therefore & \mathrm{t}_{\mathrm{l} / 2}=\frac{0.693}{0.1155 \mathrm{~h}^{-1}}=6 \text { hour }
\end{array}$
Asked in: MHT CET 2024 (04 May Shift 2)
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