What is the effective capacitance (in $\mu \mathrm{F}$ ) between points $X$ and $Y ?$

Question

Aicharya · Accepted Answer

Equivalent circuit,

Here, $\frac{C_{1}}{C_{3}}=\frac{C_{2}}{C_{4}}$
Hence, no charge will flow through $20 \mu \mathrm{F}$

$C_{1}$ and $C_{2}$ are in series, also $C_{3}$ and $C_{4}$ are in series. Hence, $C=3 \mu F, C^{\prime \prime}=3 \mu F$
$C^{\prime}$ and $C^{\prime \prime}$ are in parallel.
So, the effective capacitance will be $=3+3=6 \mu \mathrm{F}$

What is the effective capacitance (in $\mu \mathrm{F}$ ) between points $X$ and $Y ?$

Solution