What is the $\mathrm{pH}$ of $0.005 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ solution?
What is the $\mathrm{pH}$ of $0.005 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ solution?
- 5.0
- 2.3
- 3.3
- 2.0
Solution
$\begin{aligned} & \mathrm{H}_2 \mathrm{SO}_4 \longrightarrow 2 \mathrm{H}^{+}+\mathrm{SO}_4^{2-} \\ & {\left[\mathrm{H}_2 \mathrm{SO}_4\right]=0.005 \mathrm{M}} \\ & {\left[\mathrm{H}^{+}\right]=2 \times 0.005=0.01 \mathrm{M}} \\ & \mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]=-\log 0.01 \\ & \mathrm{pH}=2\end{aligned}$
Asked in: MHT CET 2021 (24 Sep Shift 2)
Practice more Ionic Equilibria questions on Aicharya