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What is the dimensional formula of $a b^{-1}$ in the equation…
What is the dimensional formula of $a b^{-1}$ in the equation $\left(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^2}\right)(\mathrm{V}-\mathrm{b})=\mathrm{RT}$, where letters have their usual meaning.
$\left[\mathrm{M}^{-1} \mathrm{~L}^5 \mathrm{~T}^3\right]$ $\left[\mathrm{M}^6 \mathrm{~L}^7 \mathrm{~T}^4\right]$ $\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$ $\left[\mathrm{M}^0 \mathrm{~L}^3 \mathrm{~T}^{-2}\right]$
Solution
$\because[\mathrm{V}]=[\mathrm{b}]$
$\therefore$ Dimension of $b=\left[\mathrm{L}^3\right]$
$\begin{aligned}
& \&[\mathrm{P}]=\left[\frac{\mathrm{a}}{\mathrm{V}^2}\right] \\
& {[\mathrm{a}]=\left[\mathrm{PV}^2\right]=\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\left[\mathrm{L}^6\right]}
\end{aligned}$
Dimension of $\mathrm{a}=\left[\mathrm{ML}^5 \mathrm{~T}^{-2}\right]$
$\therefore \mathrm{ab}^{-1}=\frac{\left[\mathrm{ML}^5 \mathrm{~T}^{-2}\right]}{\left[\mathrm{L}^3\right]}=\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]$
Asked in: JEE Main 2024 (05 Apr Shift 2)
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