What is the constant external pressure of an ideal gas when expanded from $2 \times 10^{-2} \mathrm{~m}^3$…

What is the constant external pressure of an ideal gas when expanded from $2 \times 10^{-2} \mathrm{~m}^3$ to $3 \times 10^{-2} \mathrm{~m}^3$, if the work done by the gas is $-5.09 \mathrm{~kJ}$ ?
  1. $5.09 \times 10^5 \mathrm{Nm}^{-2}$
  2. $1.01 \times 10^5 \mathrm{Nm}^{-2}$
  3. $2.02 \times 10^5 \mathrm{Nm}^{-2}$
  4. $5.60 \times 10^5 \mathrm{Nm}^{-2}$

Solution

$\begin{aligned} & \mathrm{W}=-\mathrm{P}_{\text {ext }}\left[\mathrm{V}_2-\mathrm{V}_1\right] \\ & \mathrm{W}=-5.09 \mathrm{~kJ} \\ & =-5090 \mathrm{~J} \\ & -5090=-\mathrm{P}_{\text {ext }}\left[3 \times 10^{-2}-2 \times 10^{-2}\right] \\ & 5090=\operatorname{Pext} \times 1 \times 10^{-2} \\ & \mathrm{P}_{\text {ext }}=509000 \mathrm{Nm}^{-2} \\ & =5.09 \times 10^5 \mathrm{Nm}^{-2}\end{aligned}$

Asked in: MHT CET 2021 (24 Sep Shift 1)

Practice more Chemical Thermodynamics questions on Aicharya