What is the conductivity of 0.05 M KCl solution if cell constant is $1.32 \mathrm{~cm}^{-1}$ and resistance…

What is the conductivity of 0.05 M KCl solution if cell constant is $1.32 \mathrm{~cm}^{-1}$ and resistance is 528 ohm?
  1. $0.0401 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$
  2. $0.0051 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$
  3. $0.0025 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$
  4. $0.0691 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$

Solution

$\begin{aligned} \text { Conductivity }(\mathrm{k}) & =\frac{\text { Cell constant }}{\mathrm{R}} \\ & =\frac{1.32 \mathrm{~cm}^{-1}}{528 \mathrm{ohm}} \\ & =0.0025 \mathrm{ohm}^{-1} \mathrm{~cm}^{-1}\end{aligned}$

Asked in: MHT CET 2024 (10 May Shift 1)

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