What is the change in potential of following cell $\mathrm{Zn}(\mathrm{s})\left|\begin{array}{c}\mathrm{Zn}…
What is the change in potential of following cell $\mathrm{Zn}(\mathrm{s})\left|\begin{array}{c}\mathrm{Zn} \mathrm{n}^{2+} \\ 1 \mathrm{M}\end{array}\right| \begin{gathered}\mathrm{Pb}^{2+} \\ 1 \mathrm{M}\end{gathered} \mid \mathrm{Pb}(\mathrm{s})$ if concentration of ions at anode is increased 10 times?
Decreases by 0.0296 volt
Increases by 10 volt
Decreases by 10 volt
Increase by 0.0296 volt
Solution
$\mathrm{E}_{\text {cell }}=\mathrm{E}_{\text {cell }}^0-\frac{0.0591}{2} \log \frac{\left[\mathrm{Zn}^{+2}\right]}{\left[\mathrm{Pb}^{+2}\right]}$
As conc. of $\mathrm{Zn}^{+2}$ increases 10 times, $\mathrm{E}_{\text {cell }}$ decreases by 0.0296 volts.