What is the cell constant, if two platinum electrodes in conductivity cell are separated by 0.92 cm and area…

What is the cell constant, if two platinum electrodes in conductivity cell are separated by 0.92 cm and area of cross section is $1.2 \mathrm{~cm}^2$ ?
  1. $0.767 \mathrm{~cm}^{-1}$
  2. $0.906 \mathrm{~cm}^{-1}$
  3. $1.304 \mathrm{~cm}^{-1}$
  4. $1.104 \mathrm{~cm}^{-1}$

Solution

Cell constant $=\frac{l}{\mathrm{a}}=\frac{0.92 \mathrm{~cm}}{1.2 \mathrm{~cm}^2}=0.767 \mathrm{~cm}^{-1}$

Asked in: MHT CET 2024 (03 May Shift 2)

Practice more Electrochemistry questions on Aicharya