What is the bond order of $\mathrm{B}_{2}$ molecule?

What is the bond order of $\mathrm{B}_{2}$ molecule?
  1. 0
  2. 1
  3. 3
  4. 2

Solution

Bond order $=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{4-2}{2}=1$

Asked in: MHT CET 2020 (16 Oct Shift 1)

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