What is the bond order of $\mathrm{Be}_{2}$ molecule?

What is the bond order of $\mathrm{Be}_{2}$ molecule?
  1. 2
  2. 3
  3. 0
  4. 1

Solution

In $\mathrm{Be}_{2}$ molecule, $\sigma_{1s^{2}} \sigma_{1s^{2}}^{*} \sigma_{2 s^{2}} \sigma_{2 s^{2}}^{*}$ $N_{b}=4 \quad N_{a}=4$ Bond order $=\frac{N_{b}-N_{a}}{2}=0$

Asked in: MHT CET 2020 (20 Oct Shift 2)

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