What is the bond order in $\mathrm{N}_{2}$ Molecule?

1. 2
2. zero
3. 1
4. 3

Solution

$\therefore$ Bond order $=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{8-2}{2}=3$

Asked in: MHT CET 2020 (19 Oct Shift 1)

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