What is the area of a rectangle whose length is $(3x + 2)$ and breadth is $(2x - 5)$?

What is the area of a rectangle whose length is $(3x + 2)$ and breadth is $(2x - 5)$?
  1. $6x^{2} - 11x - 10$
  2. $6x^{2} + 11x - 10$
  3. $5x - 3$
  4. $6x^{2} - 11x + 10$

Solution

Area = $(3x+2)(2x-5) = 6x^{2} - 15x + 4x - 10 = 6x^{2} - 11x - 10$.

Asked in: IMO

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