What is rate constant of a first order reaction if $60 \%$ reactant decompose in 45 minute?
What is rate constant of a first order reaction if $60 \%$ reactant decompose in 45 minute?
- 0.010 minute $^{-1}$
- 0.015 minute $^{-1}$
- 0.020 minute $^{-1}$
- 0.025 minute $^{-1}$
Solution
If $[\mathrm{A}]_0=100$, then $[A]_t=100-60=40$
For a first order reaction,
$\begin{aligned}
\mathrm{k} & =\frac{2.303}{\mathrm{t}} \log _{10} \frac{[\mathrm{~A}]_0}{[\mathrm{~A}]_{\mathrm{t}}} \\
& =\frac{2.303}{45 \mathrm{~min}} \log _{10} \frac{100}{40} \\
\therefore \quad & =\frac{2.303 \times 0.397}{45 \mathrm{~min}} \\
& =0.020 \text { minute }^{-1}
\end{aligned}$
Asked in: MHT CET 2024 (03 May Shift 2)
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