What is oxidation state of $\mathrm{Mn}$ in $\mathrm{MnO}_4^{-1}$ ?
What is oxidation state of $\mathrm{Mn}$ in $\mathrm{MnO}_4^{-1}$ ?
- $+5$
- $+6$
- $+4$
- $+7$
Solution
Let O.S. of $\mathrm{Mn}$ is $\mathrm{x}$
$\therefore \mathrm{x}+4(-2)=-1$
$x=+7$
Asked in: MHT CET 2022 (06 Aug Shift 1)
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