What is oxidation number of Ru in $\left[\mathrm{Ru}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{H}_{2}…
What is oxidation number of Ru in $\left[\mathrm{Ru}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{H}_{2} \mathrm{O}\right] \mathrm{Cl}_{2} ?$
- $+6$
- $+5$
- $+1$
- $+2$
Solution
$\mathrm{NH}_{3}$ and $\mathrm{H}_{2} \mathrm{O}$ are neutral molecules.
$\therefore$ Oxidation number of $\mathrm{Ru}=+2$
Asked in: MHT CET 2020 (15 Oct Shift 2)
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