What is new temperature of a gas when its initial volume $3 \mathrm{dm}^3$ at $300 \mathrm{~K}$ is doubled…

What is new temperature of a gas when its initial volume $3 \mathrm{dm}^3$ at $300 \mathrm{~K}$ is doubled at constant pressure?
  1. $450 \mathrm{~K}$
  2. $600 \mathrm{~K}$
  3. $750 \mathrm{~K}$
  4. $900 \mathrm{~K}$

Solution

$\begin{array}{ll} & \text { Using Charles' law, } \\ & \frac{\mathrm{V}_1}{\mathrm{~T}_1}=\frac{\mathrm{V}_2}{\mathrm{~T}_2} \\ \therefore \quad & \frac{3 \mathrm{dm}^3}{300 \mathrm{~K}}=\frac{2 \times 3 \mathrm{dm}^3}{\mathrm{~T}_2} \\ \therefore \quad & \mathrm{T}_2=\frac{2 \times 3 \times 300}{3}=600 \mathrm{~K}\end{array}$

Asked in: MHT CET 2023 (10 May Shift 1)

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