What is Henry's law constant if solubility of a gas in water at $298 \mathrm{~K}$ and 1 bar pressure is $7…

What is Henry's law constant if solubility of a gas in water at $298 \mathrm{~K}$ and 1 bar pressure is $7 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}$
  1. $2.0 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}$
  2. $7.0 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}$
  3. $3.5 \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}$
  4. $3.1 \times 10^{-5} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{bar}^{-1}$

Solution

Solubility $=\mathrm{K}_{\mathrm{H}} \times$ pgas $7 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1}=\mathrm{K}_{\mathrm{H}} \times 1$ bar $\mathrm{K}_{\mathrm{H}}=7 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \cdot \mathrm{bar}^{-1}$

Asked in: MHT CET 2021 (22 Sep Shift 2)

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