What is effective atomic number of Fe in $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$ (At. no. of…
What is effective atomic number of Fe in $\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}$ (At. no. of $\mathrm{Fe}=26$ )
- 34
- 26
- 36
- 35
Solution
$\mathrm{Z}=26, \mathrm{X}=2, \mathrm{Y}=12$
$\mathrm{EAN}=\mathrm{Z}-\mathrm{X}+\mathrm{Y}=26-2+12=36$
Asked in: MHT CET 2020 (12 Oct Shift 1)
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