What is bond angle $\mathrm{F}-\mathrm{B}-\mathrm{F}$ in $\mathrm{BF}_3$ ?
- $107^{\circ}$
- $104.5^{\circ}$
- $120^{\circ}$
- $109.5^{\circ}$
Solution

Each $\mathrm{F}-\mathrm{B}-\mathrm{F}$ bond angle in $\mathrm{BF}_3$ molecule is $120^{\circ}$.
Asked in: MHT CET 2024 (09 May Shift 1)
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