What is boiling point of a decimolal aqueous solution of glucose if molal elevation constant for water is $0.52^{\circ} \mathrm{C} \mathrm{kg} \mathrm{mol}^{-1}$ ?

Question

Aicharya · Accepted Answer

$\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{k}_{\mathrm{b}} \cdot \mathrm{m} \ & \Delta \mathrm{T}_{\mathrm{b}}=0.52 	imes 0.1, \mathrm{~m}=0.1 	ext { (decimolal solution) } \ & =0.052^{\circ} \mathrm{C} \ & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{T}_{\mathrm{b}}-\mathrm{T}_{\mathrm{b}}^{\circ} \quad\left(\mathrm{T}_{\mathrm{b}}^{\circ}=ight.	ext { Boiling point of pure water) } \ & 0.052^{\circ} \mathrm{C}=\mathrm{T}_{\mathrm{b}}-100^{\circ} \mathrm{C} \ & \mathrm{T}_{\mathrm{b}}=100.052^{\circ} \mathrm{C} \end{aligned}$

What is boiling point of a decimolal aqueous solution of glucose if molal elevation constant for water is $0…

Solution