What is atomic radius of an element if it crystallises in BCC structure with edge length of unit cell 287 pm ?

Question

Aicharya · Accepted Answer

For bec unit cell, $4 r=\sqrt{3} a$ $	herefore \quad r=\frac{\sqrt{3}}{4} a=\frac{1.732 	imes 287}{4}=124 \mathrm{pm}$

Solution