What equal length of an iron wire and a copper-nickel alloy wire, each of $2 mm$ diameter connected parallel to give an equivalent resistance of $3 Ω$ ?
(Given resistivities of iron and copper-nickel alloy wire are $12 μΩ cm$ and $51 μΩ cm$ respectively)

Question

What equal length of an iron wire and a copper-nickel alloy wire, each of

2 mm

diameter connected parallel to give an equivalent resistance of

3 Ω

?
(Given resistivities of iron and copper-nickel alloy wire are

12 μΩ cm

and

51 μΩ cm

respectively)

Aicharya · Accepted Answer

R 1 R 2 R 1 + R 2 = 3 &#160; &#937; &#961; 1 &#961; 2 &#961; 1 + &#961; 2 &#215; &#8467; A = 3 &#160; &#937; &#8467; = 3 &#215; A &#215; &#961; 1 + &#961; 2 &#961; 1 &#961; 2 = 3 &#215; &#960; 10 &#8722; 3 2 &#215; 63 &#215; 10 &#8722; 8 12 &#215; 10 - 8 51 &#215; 10 &#8722; 8 &#8467; &#8776; 97 &#160; m

What equal length of an iron wire and a copper-nickel alloy wire, each of 2   mm diameter connected…

Solution

What equal length of an iron wire and a copper-nickel alloy wire, each of 2 &#160; mm diameter connected…

Solution

What equal length of an iron wire and a copper-nickel alloy wire, each of 2 mm diameter connected…