When an aldehyde $(R-\mathrm{CHO})$ reacts with Tollen's reagent, the following reaction takes place :
$\begin{aligned} & R-\mathrm{CHO}+\underset{\text { (Tollen's reagent) }}{2\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}}+3 \mathrm{OH}^{-} \longrightarrow \\ & R \mathrm{COO}^{-}+2 \mathrm{Ag}+4 \mathrm{NH}_3+2 \mathrm{H}_2 \mathrm{O}\end{aligned}$
Thus, the products formed are, $\mathrm{Ag}, \mathrm{H}_2 \mathrm{O}, R \mathrm{COO}^{-}$ and $\mathrm{NH}_3$ and option (c) is the correct answer.