What are the oxidation numbers of $\mathrm{S}$ atoms in $\mathrm{S}_4 \mathrm{O}_6^{2-}$ ?

Question

Aicharya · Accepted Answer

When an atom is bonded to similar atoms, has zero oxidation state. $\therefore$ Two middle sulphur atoms have zero oxidation state. For other two sulphur atoms. $2 x+6 \times(-2)=-2$ $2 x-12=-2$ $\begin{aligned} 2 x & =-2+12 \\ 2 x & =+10 \\ x & =+5\end{aligned}$ $\therefore$ The oxidation number on $\mathrm{S}$-atoms in $\mathrm{S}_4 \mathrm{O}_6^{2-}$ is $+5,0,0+5$

What are the oxidation numbers of $\mathrm{S}$ atoms in $\mathrm{S}_4 \mathrm{O}_6^{2-}$ ?

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