What are ' $\mathrm{X}$ ' and ' $\mathrm{Y}$ ' respectively in the following reaction sequence?…

What are ' $\mathrm{X}$ ' and ' $\mathrm{Y}$ ' respectively in the following reaction sequence? $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_3 \stackrel{\mathrm{X}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}_2 \mathrm{H} \stackrel{\mathrm{Y}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{OH}$
  1. $\mathrm{X}=\mathrm{PCC}$; $\mathrm{Y}=\text { (i) } \quad \mathrm{B}_2 \mathrm{H}_6$ (ii) $\mathrm{H}_3 \mathrm{O}^{+}$
  2. $\mathrm{X}=\text { (i) } \mathrm{KMnO}_4 / \mathrm{OH}^{-} ; \quad \mathrm{Y}=\mathrm{NaBH}_4$ (ii) $\mathrm{H}_3 \mathrm{O}^{+}$
  3. $\mathrm{X}=\text { (i) } \mathrm{KMnO}_4 / \mathrm{OH}^{-}, \Delta ; \quad \mathrm{Y}=\text { (i) } \mathrm{B}_2 \mathrm{H}_6$ (ii) $\mathrm{H}_3 \mathrm{O}^{+}$(ii) $\mathrm{H}_3 \mathrm{O}^{+}$
  4. $\mathrm{X}=\mathrm{PCC} ; \quad \mathrm{Y}=\mathrm{LAH}$

Solution


$\mathrm{X}=$ (i) $\mathrm{KMnO}_4 / \mathrm{OH}^{-}, \Delta$, (ii) $\mathrm{H}_3 \mathrm{O}^{+}$(for strong side - chain oxidation) $\mathrm{Y}=$ (i) $\mathrm{B}_2 \mathrm{H}_6$, (ii) $\mathrm{H}_3 \mathrm{O}^{+}$(for reduction to alcohols)

Asked in: AP EAMCET 2023 (16 May Shift 2)

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