What are $X$ and $Y$ respectively in the following reaction? $Z$-product $\stackrel{Y}{\longleftarrow}…

What are $X$ and $Y$ respectively in the following reaction? $Z$-product $\stackrel{Y}{\longleftarrow} 2$-butyne $\stackrel{X}{\longrightarrow} E$-product
  1. $\mathrm{Na} / \mathrm{NH}_3$ (liq. ) and $\mathrm{Pd} / \mathrm{BaSO}_4+\mathrm{H}_2$
  2. $\mathrm{Ni} / 140^{\circ} \mathrm{C}$ and $\mathrm{Pd} / \mathrm{BaSO}_4+\mathrm{H}_2$
  3. $\mathrm{Ni} / 140^{\circ} \mathrm{C}$ and $\mathrm{Na} / \mathrm{NH}_3$ (liq. )
  4. $\mathrm{Pd} / \mathrm{BaSO}_4+\mathrm{H}_2$ and $\mathrm{Na} / \mathrm{NH}_3$ (liq.)

Solution


Hence, reagent $X$ and $Y$ are respectively $\mathrm{Na}$, $\mathrm{NH}_3$ and $\mathrm{Pd} / \mathrm{BaSO}_4+\mathrm{H}_2$.

Asked in: AP EAMCET 2008

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