What amount of conc. $\mathrm{H}_2 \mathrm{SO}_4$ solution should be used to prepare $500 \mathrm{~mL}$ of…

What amount of conc. $\mathrm{H}_2 \mathrm{SO}_4$ solution should be used to prepare $500 \mathrm{~mL}$ of $0.5 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4$ ? (The concentration of $\mathrm{H}_2 \mathrm{SO}_4$ solution being used is $90 \%$ and molecular mass of $\mathrm{H}_2 \mathrm{SO}_4=98.079 \mathrm{~g} \mathrm{~mol}^{-1}$ )
  1. $22.06 \mathrm{~g}$
  2. $24.52 \mathrm{~g}$
  3. $11.03 \mathrm{~g}$
  4. $27.24 \mathrm{~g}$

Solution

$$ \begin{aligned} & \text { (d) } M=\frac{\operatorname{mass}(\mathrm{m})}{\text { molar mass } \times \text { volume }(\mathrm{L})} \\ & \text { Given, } \quad M=0.5 \mathrm{M} \\ & \text { Molar mass }=98.079 \\ & \qquad \begin{aligned} V & =500 \mathrm{~mL}=0.5 \mathrm{~L} \\ 0.5 & =\frac{m}{98.079 \times 0.5} \Rightarrow m=24.52 \mathrm{~g} \end{aligned} \end{aligned} $$ $\because$ Concentration of $\mathrm{H}_2 \mathrm{SO}_4=90 \%$ $\therefore$ Mass of solution required $=27.24 \mathrm{~g}$.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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